Re: visual problem on two triplets in 4/4 time

[Keith E OHara]

>   My mother found a problem when I write continuous triplets. For example,
> \time 4/4 c'4 c' \times 2/3 { c'8 d' e' } \times 2/3 { f' g' a' }
> The two triplets are grouped like one sextupplet, but with two 3's. What's the 
> problem? Is it a wrong practice in notation convention? Is it controlled by 
> beam settings?

There must be something else in your score that changes the grouping.  The 
lines below give me two separately-beamed triplets.

\version "2.12.3" % and 2.13 gives the same output
{ \time 4/4 c'4 c' \times 2/3 { c'8 d' e' } \times 2/3 { f' g' a' }
}