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Re: [igraph] multiple edges and their attributes
From: |
Tamas Nepusz |
Subject: |
Re: [igraph] multiple edges and their attributes |
Date: |
Wed, 11 Mar 2015 21:55:39 +0100 |
User-agent: |
Mutt/1.5.23 (2014-03-12) |
Hi,
The following snippet gives you the edge indices of all the edges in the graph
with multiplicity > 1:
eids = [index for index, is_multiple in enumerate(graph.is_multiple()) if
is_multiple]
If you need the actual edges, then do the following once you have the indices:
graph.es[eids]
--
T.
On 03/11, Jey Narasimhan wrote:
> Hi,
>
> I am looking for an efficient way to extract all the multiple edges
> and working on them before deleting them from the graph.
>
> I have come up with the following way to extract them, but since I am
> a beginner of igraph, I am not sure about the efficiency, or if some
> operations could be done in less steps, perhaps using simplify
> function. Please comment.
>
>
> import igraph as ig
> import numpy as np
>
> myg1 = ig.Graph.Read_GraphML(sys.argv[1])
> multval = myg1.is_multiple()
> locsuniqval = np.where(np.asarray(multval)==False)[0]
> uniqedges_cm = myg1.count_multiple(locsuniqval)
> uniq_cm = np.where(np.asarray(uniqedges_cm)>1)[0]
> nonmultedges = ig.EdgeSeq(myg1, locsuniqval[uniq_cm])
> for nm in nonmultedges:
> tempdict={}
> for name in nm.attribute_names():
> tempdict[name]=[]
> for e in myg1.es.select(_within=[nm.source, nm.target]):
> if e.tuple == nm.tuple:
> for name, val in e.attributes().iteritems():
> tempdict[name].append(val)
> else:
> print 'something wrong'
> print tempdict
>
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--
T.