Re: [igraph] using variables to call a graph

[Gábor Csárdi]

Hi, it would really help to have a complete, reproducible example. Or at least the complete code. 

If you really have the names of the objects in `nets`, that won't work this way. I could help you make it work, but it is actually bad practice to store names of objects instead of storing the objects themselves.

Put the networks themselves in a list, (see ?list), and then in your loop do 

g <- nets[[i]]

Btw. 1:length(nets) is bad practice, too. It fails if the list/vector is empty. Might not be an issue in your case, but still, it is better to get used to writing seq_along(nets) instead.

Gabor

On Fri, Jan 16, 2015 at 9:14 AM, Luca Rossi <address@hidden> wrote:

Hello,

I’m trying to perform a very simple task but for some reason I can’t understand what I’m doing wrong.
So forgive me if this is very simple.
I need to perform the same analysis on a rather large set of networks but.
I’ve got all the names of the networks in a vector so I was hoping to do this through a simple loop:

for (i in 1:length(nets))
{
   g <- nets[i]
V(g)$ownhiv[is.na(V(g)$ownhiv)] <- 0

[…]
}

But I’ve got an error since: Error in V(`*tmp*`) : Not a graph object

What am I doing wrong?

Thanks a lot

Luca



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