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Re: [igraph] fitting a straight line to power-law distribution
From: |
Fabio Daolio |
Subject: |
Re: [igraph] fitting a straight line to power-law distribution |
Date: |
Thu, 28 Jul 2011 11:42:01 +0200 |
Hi Narcis,
that is because, if I got it right, when a probability density function p(x) is
power-law
with an exponent alpha, i.e. p(x)~x^(-alpha),
then its complementary cumulative distribution function is also power-law (just
do
the integration from x to infinity) but with exponent -alpha+1, i.e.
P(x)~x^(-alpha+1)
On that note, I've been pointed out to a good paper about fitting empirical data
http://arxiv.org/abs/0706.1062
Sincerely,
--
Fabio
On Jul 28, 2011, at 11:25 AM, Narges Zarrabi wrote:
> Hi,
>
> I am trying to understand the fitting to the power law distribution in the
> example in link below:
> http://igraph.sourceforge.net/screenshots2.html#8
>
> However, in the following line of the example:
> lines(10:500, 10*(10:500)^(-coef(alpha)+1))
>
> I don't understand why +1 is added in the power (-coef(alpha)+1)
>
> Could anyone explain the reason ? Thanks
>
> Regards,
> Narcis
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