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From: | Tamas Nepusz |
Subject: | Re: [igraph] Maximum Common Subgraph |
Date: | Fri, 11 Mar 2011 16:58:37 +0100 |
User-agent: | Mozilla/5.0 (X11; U; Linux x86_64; en-US; rv:1.9.2.14) Gecko/20110223 Lightning/1.0b2 Thunderbird/3.1.8 |
Well, I don't expect to find it; the mapping [1, 0] would mean that vertex 0 of the second graph maps to vertex 1 of the first graph and vertex 1 of the second graph maps to vertex 0 of the first graph. Considering that graphs g and g2 have only one vertex in common (that has the same name, i.e. "B"), I wouldn't expect any subisomorphisms between the two graphs. -- Tamas |
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