Hi,
Is there an Audio Compressor available in Octave?
I'm compressing my noises in the worst way, as you can see in the "while" condition on the example below.
In my way, the peaks will be "clipped", and I would like to avoid my stupid workaround:
====================
crest_factor = 6;
typenoise = noise(10*44100, 1, 'pink');
[z, p, k] = butter(4, [100/(44100/2), 500/(44100/2)]);
sos = zp2sos (z, p, k);
filtered = sosfilt(sos, typenoise);
normalized = filtered / (rms(filtered) / 10^(-crest_factor/20));
#{
Now I'm making an stupid workaround, as the audio file must be in
a range from -1 to +1:
#}
while (normalized(normalized > 1) || normalized(normalized < -1))
normalized(normalized > 1) = 1;
normalized(normalized < -1) = -1;
normalized = normalized / (rms(normalized) / 10^(-crest_factor/20));
endwhile
audiowrite ('AudioFile.wav', normalized, 44100);
I'm not aware there is an equivalent function on Octave to the Matlab compressor, but if I might make a couple of comments on the code:
1. Your while loop looks very strange to me and I believe the identical result would be achieved much faster by simply omitting the while and endwhile statements.
2. The statement:
normalized = filtered / (rms(filtered) / 10^(-crest_factor/20));
normalises the signal to an RMS level of -6dB below 1. An RMS below 1 does not of
course guarantee there will be no samples greater than 1, but unless your signal is very
peculiar I would expect there to be very few or none.
Possibly therefore the following code would meet your needs without the need for complex compression.
crest_factor = 6;
typenoise = noise(10*44100, 1, 'pink');
[z, p, k] = butter(4, [100/(44100/2), 500/(44100/2)]);
sos = zp2sos (z, p, k);
filtered = sosfilt(sos, typenoise);
normalized = filtered / (rms(filtered) / 10^(-crest_factor/20));
NumberOfClippedSamples = nnz(
normalized > 1 |normalized<-1)
normalized(normalized > 1) = 1;
normalized(normalized < -1) = -1;
I hope this helps.
Cheers... Ian