|
| From: | fibonacci4 |
| Subject: | Re: Derivative question |
| Date: | Fri, 1 Feb 2019 05:14:29 +0100 |
| User-agent: | Mozilla/5.0 (X11; Linux x86_64; rv:60.0) Gecko/20100101 Thunderbird/60.2.1 |
Am 01.02.19 um 03:54 schrieb bikebuilder63:
Given: t=0:0.1:20; y=t.^3-2*t; 1. how long is vector t? 2. Write the matlab/octave commodes to take the derivative of y with respect to t calling it dydt 3. what is the length of dydt? -- Sent from: http://octave.1599824.n4.nabble.com/Octave-General-f1599825.html
Homework??
| [Prev in Thread] | Current Thread | [Next in Thread] |