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Re: format datestr
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From: |
Thomas D. Dean |
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Subject: |
Re: format datestr |
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Date: |
Sun, 17 Jun 2018 14:12:59 -0700 |
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User-agent: |
Mozilla/5.0 (X11; Linux x86_64; rv:52.0) Gecko/20100101 Thunderbird/52.8.0 |
On 06/17/18 05:52, Luca Salardi wrote:
hi,
i try to code it :
ff=datestr ("23/12/2008", "dd/mm/yyyy")
but i see this error:
error: datevec: none of the standard formats match the DATE string
Help datestr is not clear on this. Nor, is help datevec.
Your DATE is not in the correct format.
From help datevec,
A date vector is a row vector with six members, representing the
year, month, day, hour, minute, and seconds respectively.
Your DATE string contains day, month, and year respectively.
You should use year, month, and day in the DATE string.
octave:41> ff=datestr ("2008/12/23", "dd/mm/yyyy")
ff = 23/12/2008
Tom Dean