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## Re: Indexing functions?

**From**: |
denizyazgac |

**Subject**: |
Re: Indexing functions? |

**Date**: |
Mon, 9 Oct 2017 05:38:54 -0700 (MST) |

Thanks !
I also write as cell
x=1:1:10;
for index=1:1:length(x);
f{index}=@(y) y*x(index).^2;
end
But problem is, I always give some value to y.
But I want to obtain functions like
f(1)= Y*1^2
f(2)=Y*2^2
f(3)=Y*3^2
because I will also make some substraction from experimental data for *each
f* and use that sum of differences for differential evaluation.
So I should cover Y unknown till the end for optimisation. Main parameter is
Y.
So, there should be a cost function like
x=1:1:10;
for index=1:1:length(x);
f{index}=@(y) y*x(index).^2;
end
x=1:1:10;
for jindex=1:1:length(x);
cost_fun_array{jindex}=@(Y) abs(*f{jindex}*-exp_data(jindex))
%%But I can not call f{jindex} beacause Octave push me to give a value to Y;
in that case I can not carry on optimisation
cost_fun=sum(cost_fun_array)
--
Sent from: http://octave.1599824.n4.nabble.com/Octave-General-f1599825.html