|Subject:||Re: Help in leasqr|
|Date:||Mon, 29 Aug 2016 08:55:51 +0200|
|User-agent:||Mozilla/5.0 (Windows NT 6.1; WOW64; rv:45.0) Gecko/20100101 Thunderbird/45.2.0|
Am 26.08.2016 um 17:36 schrieb Bharath R:
Maybe I am misunderstanding the task, but if you have T measured, you can calculate dT/dt with just
Now you have your lefthand side (it's one element shorter than T, handle this in a sensible way, e.g. by appending something to y or discarding one element from T later on) and might be able to use leasqr as before.
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