
From:  Bharath R 
Subject:  Re: Help in leasqr 
Date:  Fri, 26 Aug 2016 17:36:35 +0200 
The problem is that some of your parameters are redundant. As for yourOn Fri, Aug 26, 2016 at 12:17:04PM +0200, Bharath R wrote:
> Hello all,
>
> Thank you very much for such a helpful forum. I am using Octave for the
> past couple of days. I have been working to get the parameters that best
> fit my function.
>
> Function: g=@(x,p)
> [(p(1).*p(2).*x(:,1)+(p(3).*x(:,2))+(p(4)*p(5)))./((p(1)*p( 2))+p(3))]
>
> where p indicates the parameters , x indicates the independent variables
> and y is measured variable.
> [pin]=1.0000e002
> 1.0000e+003
> 1.0000e+002
> 1.0000e002
> 1.0000e+003
>
> [x]=21.33700 0.80000
> 21.28800 0.10000
> 20.55900 0.80000
> 21.21800 1.40000
> 20.68600 1.70000
>
> [y] = 19.545
> 19.300
> 19.300
> 19.137
> 19.000
>
> When I run this function ([f, p, cvg, iter]=leasqr(x,y,pin,g)) with leasqr
> function it gives me the following result:
>
> CONVERGENCE NOT ACHIEVED!
> f =
>
> 19.710
> 19.578
> 18.827
> 19.326
> 18.824
>
> p =
>
> 1.6953e001
> 1.6258e+003
> 4.0087e+001
> 7.8664e002
> 3.9346e+003
>
> cvg = 0
> iter = 20
>
> I would like to know what does "f" in result give as output. Is it giving
> me the output of function "g" after implementing the newly calculated
> parameters or is it something else? If it is the output of g, then I feel
> it is relatively closer to the measured data (y). yet it is showing "
> CONVERGENCE NOT ACHIEVED!".
>
> Also , I would like to know how do I implement a differential equation in
> leasqr to calculate the parameters. I look forward to your answer.
>
> Thanks and regards,
> Bharathy
question, the returned values should be those of the best fit achieved
so far by the algorithm. They might be almost equivalent to the
parameters, after convergence, of an equivalent problem formulated
without redundant parameters.
For the record, I recommend using nonlin_curvefit (or nonlin_residmin)
instead of leasqr.
Olaf

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