help-octave
[Top][All Lists]
Advanced

[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]

Re: Finding the coeffecent of the transfer function from the poles.


From: Doug Stewart
Subject: Re: Finding the coeffecent of the transfer function from the poles.
Date: Fri, 3 Jun 2016 15:51:07 -0400



On Fri, Jun 3, 2016 at 3:44 PM, Doug Stewart <address@hidden> wrote:


On Fri, Jun 3, 2016 at 2:49 PM, shank1207 <address@hidden> wrote:
How do you find the transfer function from the poles for example i have the
given poles p1=-0.54887 + 0.89513*i and p2=-0.54887 - 0.89513*i; I want to
find the coefficient of the transfer function which is 1, 1.09774 and 1.1025
(s^2+1.0977s+1.1025)

Thanks



--
View this message in context: http://octave.1599824.n4.nabble.com/Finding-the-coeffecent-of-the-transfer-function-from-the-poles-tp4677412.html
Sent from the Octave - General mailing list archive at Nabble.com.

_______________________________________________
Help-octave mailing list
address@hidden
https://lists.gnu.org/mailman/listinfo/help-octave

p1=-0.54887 + 0.89513*i
p2=-0.54887 - 0.89513*i

d=poly([p1 p2])





--
DAS


clear

p1=-0.54887 + 0.89513*i
p2=-0.54887 - 0.89513*i

d=poly([p1 p2])


#or this

n=1
sys1=tf(n,d)


--
DAS


reply via email to

[Prev in Thread] Current Thread [Next in Thread]