Re: Vectorizing simple loops

[Francesco Potortì]

>Brian - sure, you are welcome. I learned a lot to reuse later too. Indeed the
>solution is very elegant, I never suspected such would be possible. I am
>pasting it here too, for reference:
>
>in = [ 1 0 2 0 7 7 7 0 5 0 0 0 9 ]
>out = nonzeros(in).'(cumsum(in~=0))

Since this is a help list, here is a hint for those that are not
proficient in Octave.

The .' operator in this case (real numbers) is the same as the '
(transpose) operator, and is only needed to obtain a horizontal vector.

So this is equivalent to:

n = nonzeros(in)'
out = n((cumsum(in!=0))

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