Re: Solving 4 quadratic equations with four unknowns

[Macy]

yes. and they each don't even have to equal zero.

--- address@hidden wrote:

From: scjoshi <address@hidden>
To: address@hidden
Subject: Solving 4 quadratic equations with four unknowns
Date: Mon, 11 Aug 2014 04:05:33 -0700 (PDT)

I have four equations:
f1 (x1, x2, x3, x4, x1*x3, x1*x4, x2*x3, x2*x4)=0
f2 (x1, x2, x3, x4, x1*x3, x1*x4, x2*x3, x2*x4)=0
f3 (x1, x2, x3, x4, x1*x3, x1*x4, x2*x3, x2*x4)=0
f4 (x1, x2, x3, x4, x1*x3, x1*x4, x2*x3, x2*x4)=0

Is there any way of solving these four quadratic equations in octave?