Re: Min function problem

[Kai Torben Ohlhus]

On Sun, Jan 12, 2014 at 3:51 AM, plamen <address@hidden> wrote:

Hello,
I am having the following problem

for j1=1:length(index1)
                            for j2=1:length(index2)
                                B(j1,j2)=abs(f(index1(j1))-f(index2(j2)));
                            end
                            [minB(j1), iminB(j1)]=min(B(j1,:));
                            if (minB(j1)<=some_value)

C(index2(iminB(j1)),j)=A(index2(iminB(j1)),j);


and when I run the script I am getting an error message A(I): index out of
bounds; value 2 out of bound 1
on the line where I call index(iminB(j1))

How is that possible, whereas the values of iminB are chosen between the
index of index2?
Thanks for your advice
Plamen



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Hello Plamen,

can you provide a minimal and executable code sample (with e.g. your input data, as I have no clue about the dimensions of these values).

Best,

Kai