Re: SQP - Reducing Vector Size?

[jjmilburn]

After posting, I noticed that the problem may be that the initial x0 was
defined as a scalar, and this was affecting the result.  I changed the
initial x0 to be the same size as "w", and now the error that occurs is:

octave:69> sqp(qw, @(w)cost(w),[],@(w)conEq(w))
error: operator *: nonconformant arguments (op1 is 50x51, op2 is 1x51)
error: evaluating argument list element number 1
error: evaluating argument list element number 1
error: called from:
error:   /usr/share/octave/3.2.4/m/optimization/qp.m at line 238, column 19
error:   /usr/share/octave/3.2.4/m/optimization/sqp.m at line 414, column 34
error:   /home/josh/octaveExperiment/data/trainSVM.m at line 44, column 7

I am passing sqp a 1x51 decision variable vector.  On a hunch, I changed my
funcition call to the following (qw transposed, or qw' as the initial
condition):

octave:69> sqp(qw', @(w)cost(w),[],@(w)conEq(w))

This worked, and it appears to run.  I will continue to examine this, but
can someone confirm if sqp will only accept column vectors, not row vectors?

Thanks,




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