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why cell arrays are used in 'interp2'
From: |
Sergei Steshenko |
Subject: |
why cell arrays are used in 'interp2' |
Date: |
Mon, 24 Dec 2012 19:25:14 -0800 (PST) |
Hello,
looking into 'octave-3.6.2/share/octave/3.6.2/m/general/interp2.m' file I see:
"
265 ## construct the cubic hermite base functions in x, y
266
267 ## formulas:
268 ## b{1,1} = ( 2*t.^3 - 3*t.^2 + 1);
269 ## b{2,1} = h.*( t.^3 - 2*t.^2 + t );
270 ## b{1,2} = (-2*t.^3 + 3*t.^2 );
271 ## b{2,2} = h.*( t.^3 - t.^2 );
272
273 ## optimized equivalents of the above:
274 t1 = tx.^2;
275 t2 = tx.*t1 - t1;
276 xb{2,2} = hx.*t2;
277 t1 = t2 - t1;
278 xb{2,1} = hx.*(t1 + tx);
279 t2 += t1;
280 xb{1,2} = -t2;
281 xb{1,1} = t2 + 1;
282
283 t1 = ty.^2;
284 t2 = ty.*t1 - t1;
285 yb{2,2} = hy.*t2;
286 t1 = t2 - t1;
287 yb{2,1} = hy.*(t1 + ty);
288 t2 += t1;
289 yb{1,2} = -t2;
290 yb{1,1} = t2 + 1;
291
292 ZI = zeros (size (XI));
293 for i = 1:2
294 for j = 1:2
295 zidx = sub2ind (size (Z), yidx+(j-1), xidx+(i-1));
296 ZI += xb{1,i} .* yb{1,j} .* Z(zidx);
297 ZI += xb{2,i} .* yb{1,j} .* DX(zidx);
298 ZI += xb{1,i} .* yb{2,j} .* DY(zidx);
299 ZI += xb{2,i} .* yb{2,j} .* DXY(zidx);
300 endfor
301 endfor
".
It looks to me only numeric data is used as array elements, so why cell arrays
and not regular 2d matrices ?
Speed ? Space ? Something else I couldn't think of ?
Thanks,
Sergei.
- why cell arrays are used in 'interp2',
Sergei Steshenko <=
- Re: why cell arrays are used in 'interp2', Ben Abbott, 2012/12/25
- Re: why cell arrays are used in 'interp2', Sergei Steshenko, 2012/12/25
- Re: why cell arrays are used in 'interp2', Ben Abbott, 2012/12/25
- Re: why cell arrays are used in 'interp2', Sergei Steshenko, 2012/12/25
- Re: why cell arrays are used in 'interp2', Michael Goffioul, 2012/12/25
- Message not available
- Re: why cell arrays are used in 'interp2', Michael Goffioul, 2012/12/25
- Message not available
- Re: why cell arrays are used in 'interp2', Michael Goffioul, 2012/12/25
- Re: why cell arrays are used in 'interp2', c., 2012/12/25