Re: Interpolating with f(x) = a*x^b, where b might be a non-integer?

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Re: Interpolating with f(x) = a*x^b, where b might be a non-integer?

From:	Jordi Gutiérrez Hermoso
Subject:	Re: Interpolating with f(x) = a*x^b, where b might be a non-integer?
Date:	Mon, 29 Oct 2012 09:16:14 -0400

On 29 October 2012 09:10,  <address@hidden> wrote:

> If you don't need to use Octave, you might try CurveExpert
> <http://www.curveexpert.net>, or Excel's Solver works reasonably well
> if you set it up right.

Please do not advertise non-free software here.

- Jordi G. H.

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Interpolating with f(x) = a*x^b, where b might be a non-integer?, Joanna Rutkowska, 2012/10/28
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    - Re: Interpolating with f(x) = a*x^b, where b might be a non-integer?, Sergei Steshenko, 2012/10/29
    - Re: Interpolating with f(x) = a*x^b, where b might be a non-integer?, Jordi Gutiérrez Hermoso, 2012/10/29
    - Re: Interpolating with f(x) = a*x^b, where b might be a non-integer?, Sergei Steshenko, 2012/10/29
    - Re: Interpolating with f(x) = a*x^b, where b might be a non-integer?, Francesco Potortì, 2012/10/29
    - Re: Interpolating with f(x) = a*x^b, where b might be a non-integer?, Sergei Steshenko, 2012/10/29
    - Re: Interpolating with f(x) = a*x^b, where b might be a non-integer?, Francesco Potortì, 2012/10/29
    - Re: Interpolating with f(x) = a*x^b, where b might be a non-integer?, Sergei Steshenko, 2012/10/29
  - RE: Interpolating with f(x) = a*x^b, where b might be a non-integer?, Damian Harty, 2012/10/29

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