help-octave
[Top][All Lists]
Advanced

[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]

Re: Evaluate the following series:


From: Thomas Shores
Subject: Re: Evaluate the following series:
Date: Wed, 15 Aug 2012 12:33:26 -0500
User-agent: Mozilla/5.0 (Windows NT 6.1; WOW64; rv:12.0) Gecko/20120428 Thunderbird/12.0.1

Right. Actually the sum of squares formula that students confirm in algebra as an induction exercise, or use in calculus I to confirm via areas that the antiderivative of x^2 is x^3/3 is

1^2 + 2^2 + ... + n^2 = n*(2*n+1)*(n+1)/6

which gives exact answer 338350, certainly less than a million.


On 8/13/2012 2:02 PM, Przemek Klosowski wrote:
On 08/12/2012 02:45 AM, address@hidden wrote:
1^2+2^2+3^2+...+100^2.

Could this be correct, I'm getting sum=50005000?

Back of the envelope says NO: you have 100 terms that are at most 100^2, so the sum cannot be larger than one million.
_______________________________________________
Help-octave mailing list
address@hidden
https://mailman.cae.wisc.edu/listinfo/help-octave



reply via email to

[Prev in Thread] Current Thread [Next in Thread]