fminunc and for loop

[Michael Teitelbaum]

Hi,

I am trying to perform the fminunc function, but I want to use a for loop within my function, and I'm not sure exactly how to do that.

What I want is:

fminunc(f,[0,0])

where f equals the sum of:

f = @(x)((((A(i,3) / 1000 + x(1) + A(i,4) / 1000 - ((A(i,3) / 1000 + x(1) + A(i,4) / 1000) ^ 2 - 4 * A(i,3) / 1000 * A(i,4) / 1000) ^ 0.5) / 2 * 1.4e-3 - (1.4e-3 - 8e-6) * (A(i-1,3) / 1000 + x(1) + A(i-1,4) / 1000 - ((A(i-1,3) / 1000 + x(1) + A(i-1,4) / 1000) ^ 2 - 4 * A(i-1,3) / 1000 * A(i-1,4) / 1000) ^ 0.5) / 2) * x(2)) * 1e6 - A(i,1)) ^ 2

for i between 5 and  35.

If it is not possible to use a for loop within fminunc, is there a good way to get octave to write out that function for me instead of me having to write it out manually?

Any help would be greatly appreciated.

Thanks,

Michael