Re: filtering logical array

[Mike Miller]

On Tue, Jun 26, 2012 at 3:53 PM, Robert T. Short
<address@hidden> wrote:
> On 06/26/2012 11:48 AM, Jordi Gutiérrez Hermoso wrote:
>>
>> a=[0 0 1 1 1 1 1 0 1 0 1 0 0 1 0 0 1 1 0 0 0 0 0 1 1 1 0]
>
> Kind of a fun problem.  Here is another solution.

More fun than what I was doing...

> x = conv(a,[1 1 1])
> z = x>2
> z = z | shift(z,-1) | shift(z,-2)
> z = z(1:length(a))
>
> There is probably a much more elegant way to do the last two lines but it
> isn't coming to me.

I noticed your shift-and-or of z is really sort of a convolution.  How about:

x = conv(a, [1 1 1])
y = conv(x, [1 1 1])
z = y >= 6
z = z(3:end-2)

-- 
mike