Re: filtering logical array

[Robert T. Short]

On 06/26/2012 11:48 AM, Jordi Gutiérrez Hermoso wrote:
> a=[0 0 1 1 1 1 1 0 1 0 1 0 0 1 0 0 1 1 0 0 0 0 0 1 1 1 0]
Kind of a fun problem.  Here is another solution.


a = [0 0 1 1 1 1 1 0 1 0 1 0 0 1 0 0 1 1 0 0 0 0 0 1 1 1 0]
x = conv(a,[1 1 1])
z = x>2
z = z | shift(z,-1) | shift(z,-2)
z = z(1:length(a))

There is probably a much more elegant way to do the last two lines but 
it isn't coming to me.

Bob