Re: How does size() work?

[Przemek Klosowski]

On 06/19/2012 04:04 PM, Jonathan Margoliash wrote:
> CorrectionData = {"1977:3.7423:6.5548" "1978:6.7854:9.6075"};
> disp(size(CorrectionData));
..
> Why isn't correction data treated as a 1-dimensional cell array? And
> even if it's been treated as a 2-dimensional cell array, why is the
> row second? Thanks!

This just shows the roots of the Matlab language, where the primary
object was a 2D numerical array. There is no truly one-dimensional data
type: when you do x=[3 4] you get size(x) as 1 2, i.e. x is a 2D array
with one row and two columns--first index numbers rows, second--columns.

The cell array works the same way: you got a 1x2 cell array. If you 
transposed the data:
CorrectionData = {"1977:3.7423:6.5548" "1978:6.7854:9.6075"}';

you would get size(CorrectionData) equal to 2 1.