RE: HEPL FOR A FUNCTION

[CARMEN SANCHEZ]

Hi Doug:
 
Sorry, but I cannot understand to you.
 
I have this:
 
clear all;
A=[-0,195966, -0,397014, -0,538551, -0,954502;                            
-0,021981,      0,387760,   -0,593141,   -0,240908;
-0,195130,      0,013832,   -0,686614,   -0,901565;
0,134872,      0,711619,   -0,339303,      0,440442];
b=[-0,0129656;                                                                                    
0,6601410;
0,0694383;
0,3373380];
B  =  [A,  b];                                                                                          
rank (A)                                                                                                 
rank (b)
rank (B)
[R,  K]  =   rref (B)                                                                                 

I have calculate the matrix and now I want to calculate the same but now I just want both matrix with 2 decimals like this:
 
clear all;
A=[-0,19, -0,39, -0,53, -0,95; ......
 
b=[-0,012; ......                                                                         
 
How can I do it automatically?
 
thank you very much for your help.
 
Best regards,
 
Javier M. (from Spain)              

 

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Date: Thu, 19 Apr 2012 06:58:35 -0400
Subject: Re: HEPL FOR A FUNCTION
From: address@hidden
To: address@hidden
CC: address@hidden

On Thu, Apr 19, 2012 at 6:37 AM, CARMEN SANCHEZ <address@hidden> wrote:

Good morning:
 
I am using octave to resolve a matrix problem.
 
I have this matrix:
 
A=[-0,195966, -0,397014, -0,538551, -0,954502;                             
-0,021981,      0,387760,   -0,593141,   -0,240908;
-0,195130,      0,013832,   -0,686614,   -0,901565;
0,134872,      0,711619,   -0,339303,      0,440442];
 
Is there any octave function to reduce decimals to just only 2 decimals without erase them manually?
 
Best regards,
 
Javier M.
 

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try

output_precision(0)

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DAS

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