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Re: i+++j

From: Muhali
Subject: Re: i+++j
Date: Wed, 29 Feb 2012 13:12:47 -0800 (PST) 
        k = (i++) + j; disp ([i j k]) ;
           1   0   0
        k = (i++) + j; disp ([i j k]) ;
           2   0   1

well yes, but why does it not

k = i+ (++j); disp ([i j k]) ;
0  1  1

?


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