help-octave
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Re: Help


From: Liam Groener
Subject: Re: Help
Date: Sat, 18 Feb 2012 12:22:05 -0800

Sent from my iPad

On Feb 18, 2012, at 10:17 AM, pathematica <address@hidden> wrote:

> Another variation offered to give further insight into what octave does
> (rather than indulging in gratuitous competitive spirit). Honest.
> 
> (1:100)*(1:100)'
> 
> OK. Maybe it would be more honest to say "as well as" 
> 
> -----
> However good you think Octave is, it's much, much better.
If we are showing off, how about

100*101*201/6

(sum(n^2)) = n*(n+1)*(2*n+1)/6)


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