Re: Finding values that aren't in an array in octave

[Rick T]

Thanks

On Sun, Oct 9, 2011 at 4:44 AM, Juan Pablo Carbajal <address@hidden> wrote:

On Sun, Oct 9, 2011 at 4:36 PM, Rick T <address@hidden> wrote:
> a2=[1,2,3,4,5,6,7,8,9,10,11,12,13]


One way to go is
> tf = ismember (a2, a1);
> a3 = a2(! tf)
a3 =

   2    3    6    7    9   10   11   12

btw, your a3 was not correct. 13 is in a1 and 2 is missing in a1. :D


--
M. Sc. Juan Pablo Carbajal
-----
PhD Student
University of Zürich
http://ailab.ifi.uzh.ch/carbajal/

--