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From: | Rick T |
Subject: | Re: Finding values that aren't in an array in octave |
Date: | Sun, 9 Oct 2011 06:25:41 -1000 |
On Sun, Oct 9, 2011 at 4:36 PM, Rick T <address@hidden> wrote:
> a2=[1,2,3,4,5,6,7,8,9,10,11,12,13]
One way to go is
> tf = ismember (a2, a1);
> a3 = a2(! tf)
a3 =
2 3 6 7 9 10 11 12
btw, your a3 was not correct. 13 is in a1 and 2 is missing in a1. :D
--
M. Sc. Juan Pablo Carbajal
-----
PhD Student
University of Zürich
http://ailab.ifi.uzh.ch/carbajal/
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