Re: space vs semicolon - why syntax error with the former ? (octave-3.4.2)

[CdeMills]

Sergei Steshenko-2 wrote:
> 
> --- On Tue, 8/16/11, Ben Abbott <address@hidden> wrote:
> 
> 
>> Back to your example, there is more than one interpretation
>> of ...
>> 
>>     for ii = 1:1 ii endfor disp ii ;
>> 
>> Ben
>> 
> 
> 'endfor' "balances" 'for', i.e. the parser may forget _completely_ (except
> for input text pointer position) about the whole 'for' loop, and after
> that parse the 'disp' (in this case) part.
> 
> I.e. I still don't see how different interpretation can be present in
> this case - to me it looks like the 'for' loop statement is unambiguously
> over, and no special separator (e.g. ';') is necessary - simply
> because of 'endfor' detection.
> 
> 

Sorry, but taking your reasoning literally is bogus: let's consider
 if (0>1) disp('Problem'); end; disp(36)
if you take for granted that the 'end' close the expression, then then
previous line should be equivalent to
 ; disp(36)
which is a syntactically incorrect.

Regards

Pascal

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