[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]
Re: zeros of bessel functions
From: |
Liam Groener |
Subject: |
Re: zeros of bessel functions |
Date: |
Sat, 16 Jul 2011 12:50:04 -0700 |
On Jul 16, 2011, at 12:22 PM, john wrote:
>
> Hi,
>
> I'm a hobby mathematician and look for the following.
>
> Zeros of bessel functions.I found this on the internet to compute the zeros
> of bessel functions.
>
> I tried this in octave but it seems not be working.Can you help me how I
> compute the zeros of bessel
>
> functions in octave,or change the progams I found.
>
> Thank you
>
> Kind regards
>
> from Belgium
>
>
>
>
> Find Zeros Bessel Function
>
> Hi All,
>
> I want to find out the roots of J0(x) = 0. Not at just one point, but a
> whole list of them. What is the easiest way of implementing this?
>
> I can put a simple loop around fzero, but that will give me duplicates:
>
> for i = 1:1000
> f(i) = fzero((x)besselj(0,x),i);
> end
>
> Do any of you know how to implement this?
>
> Thank you very much,
>
>
>
>
>
>
>
> < 3 replies >
>
> Reply 1 >> Re: Find Zeros Bessel Function
>
> Why not just use unique on the results?
>
> Alternatively, you can use my newtzero function. It finds 202 roots, though
> they are not guaranteed to be inclusive between min and max.
>
> rt = newtzero((x)besselj(0,x),1);
>
>
> http://www.mathworks.com/matlabcentral/fileexchange/6924-newtzero
>
> Reply 2 >> Re: Find Zeros Bessel Function
>
> Thanks for your response Matt, the unique function would definitely work
> since the point are spaced roughly 'pi' apart.
>
> However, I found another way of doing this:
>
> bessj0 = inline('besselj(0,x)');
> for n = 1:n
> z(n) = fzero(bessj0,[(n-1) n]*pi);
> end
>
> just specify 'n' and it will give you the first n-values of J(z) = 0;
>
> Thanks for the help!
>
> Eelco
>
> Reply 3 >> Re: Find Zeros Bessel Function
>
> In article <hdt0ak$84r$1fred.mathworks.com>, feijooosgmail.com says...
> Thanks for your response Matt, the unique function would definitely work
> since the point are spaced roughly 'pi' apart.
>
> However, I found another way of doing this:
>
> bessj0 = inline('besselj(0,x)');
> for n = 1:n
> z(n) = fzero(bessj0,[(n-1) n]*pi);
> end
>
> just specify 'n' and it will give you the first n-values of J(z) = 0;
>
> Thanks for the help!
>
> Eelco
>
>
> You are better off using anonymous functions, if this is your strategy:
>
> bessj0 = (x) besselj(O,x)
>
> for n=1:K (shouldn't be n here)
> z(n) = fzero(bessj, etc.
> end
What doesn't work? What version of Octave are you using? I tried this and it
worked fine in octave 3.4.2:
[1] >> bessj0=@(x)besselj(0,x);
[2] >> for n=1:5
> z(n) = fzero(bessj0,[(n-1) n]*pi);
> end
[3] >> z
z =
2.4048 5.5201 8.6537 11.7915 14.9309
[4] >>