Re: re-assign special values in matrix

[Doug Stewart]

On Fri, Nov 12, 2010 at 1:04 AM, Isak Delberth Davids
<address@hidden> wrote:
> Here comes a lay-man,
>
> I intend to avoid dividing by zero, by re-assigning a different value to a
> entry that is zero in a divisor matrix. In the following code I want to
> search for that entry of A which equals zero (being A(7) in this case), and
> give it a value that is greater then zero but smaller than all other
> non-zero entries (which is A(3)=9 in this case). I am trying a if-statement
> as can be seen --- which seems WRONG. Where should I fix?
>
> % code begin
> clear;clc;
>
> a = [3; 2; 1; 3; 4; 5; 1]
> A = [12; 11; 9; 13; 67; 44; 0]
>
> min(A(A~=0)) = A(A==0) % trying to set the zero values in divisor matrix to
> the min non-zero entry?
>
> B = a./A
> % code begin
>
> regards,
>
> * * * * * * * * * * * * * * *
> *  Isak Delbert Davids *
> *  +264-81-33 049 33  *
> *  +264-61-206 3789   *
> *    Namibia, Afrika     *
> * * * * * * * * * * * * * * *
>

Try this


a = [3; 2; 1; 3; 4; 5; 1]
A = [12; 11; 9; 13; 67; 44; 0]

minA=min(A(A~=0))

 A(A==0) =minA