precision of floor(a/b)

[Tim Rueth]

If I do floor(6/1), I correctly get 6.  If I do floor(0.6/0.1), I get 5.  If I do floor((0.6/0.1 + 0.00000001)) I correctly get 6.

 

I assume this has to do with the precision of the division?  I read in the manual that Octave stores numbers as double precision, so this surprises me.  What's the best way to deal with this imprecision so I can always get the correct answer, or is something else going on here?

 

I'm on Windows Vista, if that makes a difference.

 

Thanks,

 

--Tim