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Re: Error with tf(): # of poles < # of zeros
From: |
Axax |
Subject: |
Re: Error with tf(): # of poles < # of zeros |
Date: |
Fri, 26 Mar 2010 10:47:02 +0100 |
Il giorno gio, 25/03/2010 alle 22.33 -0400, Doug Stewart ha scritto:
> Yes there is.
>
> Try doing the inverse Laplace transform on s
>
> inverse of (1/s) is a step function
> inverse of (1) is an impulse function
> inverse of (s) is ??? Well it is the derivative of the impulse
> function ---- which is a positive going impulse and a negative going
> impulse at the same time.
> Have fun doing the inverse of s^2 :-)
Oh thanks, I haven't think to follow this way :)
>
> So Octave and math in general needs the numerator to be of the same or
> less order of polynomials.
>
> If you are working in control theory and you say "yes but I can build
> the circuit and it works -- so why can't we simulate the circuit that
> I built" --- then the answer is that there are some high frequency
> poles on your opamp that you are ignoring. So just add some high
> frequency poles and keep your DC gain the same. and it will work.
hummm... I like this! Fits more the reality!
>
> 1000
> --------
> s + 1000
>
>
> My students run into this every year :-)
> Doug Stewart
>
>
Thank you!
Axel
>