fastest way to test a logical vector

[Dupuis]

Hello,

I'm analysing a signal where outliers are not uncommon. So the main loop
contains a number of test like

sum(x(indi-(1:4)) >= 0) >= 2 && sum(x(indi+(1:4)) <= 2) >= 2, 

I tried to optimise x and indi as int16, so the types are
x(indi-(1:4)) vector of int16
x(indi-(1:4)) >= 0 vector of logical
sum(x(indi-(1:4)) >= 0) double

Is there a way to avoid, in the last operation, the logical -> double
conversion ? any() doesn't fit the requirement, as it test for one value. I
thinked about
sort(x(indi-(1:4)) >= 0))(3) == 1
But this implies to call sort at each test. Does someone see a faster
solution ? I'm working with octave3.2

Regards

Pascal

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