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Re: how to calculate mean for many files


From: Sergei Steshenko
Subject: Re: how to calculate mean for many files
Date: Mon, 14 Dec 2009 07:59:30 -0800 (PST)


--- On Mon, 12/14/09, febty febriani <address@hidden> wrote:

> From: febty febriani <address@hidden>
> Subject: Re: how to calculate mean for many files
> To: "Jaroslav Hajek" <address@hidden>
> Cc: address@hidden
> Date: Monday, December 14, 2009, 1:05 AM
> thank you for your quick response. 
> I tried to do what your advice is. I replaced this:
> "filenames = # cell array of strings" with the
> folder name where I put data. But, I met error : parse
> error: syntax error.
> 
> Are there still problems?
> 
> regards,
> febty
> 
> 
> 2009/12/14 Jaroslav Hajek <address@hidden>
> 
> On Mon, Dec 14, 2009 at
> 6:55 AM, febty febriani <address@hidden>
> wrote:
> 
> > For Jaroslav, I am sorry so much. I want to send my
> email to octave forum,
> 
> > not your email.
> 
> >
> 
> > For everyone, below my problem.
> 
> > I grabbed from my previous email.
> 
> >
> 
> > ###
> 
> > I am trying to describe my problem clearer. I am sorry
> there is some
> 
> > misunderstanding with my description.
> 
> > I have many files of data (total of files is about 365
> files). Every file
> 
> > has 9 columns and 36 rows. How to find the mean of
> every row and column from
> 
> > files? For example :
> 
> >
> 
> > the first file
> 
> >
> 
> > 1   1   2   3 ...  6
> 
> > 2  2   1    4 ... 5
> 
> > .
> 
> > .
> 
> > .
> 
> > 3   4  2    1 .... 2
> 
> >
> 
> > the second file
> 
> >
> 
> > 2  1   5   3 ...  2
> 
> > 2  1   1   2 ...  1
> 
> > .
> 
> > .
> 
> > .
> 
> > 4   1  1    2 .... 1
> 
> >
> 
> >
> 
> > for above sample matrix, I will get mean for every row
> and column is
> 
> >
> 
> > 1.5   1   3.5   3  ...     4
> 
> > 2    1.5   1    3  ...     3
> 
> > .
> 
> > .
> 
> > .
> 
> > 3.5  2.5  1.5  1.5 ... 1.5
> 
> >
> 
> > ####
> 
> >
> 
> > any kind of help is appreciated.
> 
> > Thanks very much for your kind responses.
> 
> >
> 
> > Regards,
> 
> > febty
> 
> >
> 
> 
> 
> 
> 
> filenames = # cell array of strings
> 
> matrices = cellfun (@load, filenames,
> "UniformOutput", false);
> 
> means = plus (matrices{:}) / numel (matrices);
> 
> 
> 
> can you beat it... :)
> 
> 
> 
> regards
> 
> 
> 
> --
> 
> RNDr. Jaroslav Hajek
> 
> computing expert & GNU Octave developer
> 
> Aeronautical Research and Test Institute (VZLU)
> 
> Prague, Czech Republic
> 
> url: www.highegg.matfyz.cz
> 
> 
> 
> 
> -- 
> 
> ******
> febty febriani
> Indonesian Institute of Sciences
> Research Center for Physics
> Kompleks PUSPIPTEK
> Serpong, Indonesia, 15314
> 
> 
> -----Inline Attachment Follows-----
> 

Because array_of_files != folder_name.

Regards,
  Sergei.


      



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