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Re: counting totals in square grids (meshgrid)


From: Jaroslav Hajek
Subject: Re: counting totals in square grids (meshgrid)
Date: Mon, 14 Dec 2009 09:36:44 +0100

On Mon, Dec 14, 2009 at 8:41 AM, Isak Delberth Davids
<address@hidden> wrote:
> I would like to use the boundaries of the x-y grids, such that for
> example all numbers in the interval:
>
> x=0 and x<1 & y=0 and y<1 are counted as the total count of say grid-1.1
> x=1 and x<2 & y=0 and y<1 are counted as the total count of say grid-2.1
> x=2 and x<3 & y=0 and y<1 are counted as the total count of say grid-3.1
> .
> .
> .
> x=n and x<n+1 & y=0 and y<1 are counted as the total count of say grid-n.1
> .
> .
> .
> x=0 and x<1 & y=1 and y<2 are counted as the total count of say grid-1.2
> x=0 and x<1 & y=2 and y<3 are counted as the total count of say grid-1.3
> x=0 and x<1 & y=3 and y<4 are counted as the total count of say grid-1.4
> .
> .
> .
> x=0 and x<1 & y=n and y<n+1 are counted as the total count of say grid-1.n
> .
> .
> .
> and so on. I hope that makes it a bit clearer ...
>
>
> isak.davids

Huh? x=0 and x<1 is a tautology (the first implies the second) ...?

If I understand correctly, you have two vectors, x and y, of length m,
and you want to compute an nxn matrix grid so that
grid(i,j) is the count of indices k=1..m such that i-1 <= x(k) < i &&
j-1 <= y(k) < j
In octavish,
grid(i,j) = sum (i-1 <= x & x < i & j-1 <= y & y < j).

for all i,j=1:n.

Is this correct?

-- 
RNDr. Jaroslav Hajek
computing expert & GNU Octave developer
Aeronautical Research and Test Institute (VZLU)
Prague, Czech Republic
url: www.highegg.matfyz.cz


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