Re: How do you pass two Octave functions to an .oct function?

[babelproofreader]

>I compiled the code in stages and so I am sure that it is the filter code
that is the problem

The problem seems to be that the loop over the complex column vector output
of fft fails. The simple code below 

#include <octave/oct.h>
#include <octave/dColVector.h>
#include <octave/parse.h>
#include <math.h>

DEFUN_DLD (justchange, args, , "Help String")
{
  octave_value retval;
  ComplexColumnVector justchange_input = args(0).complex_column_vector_value
();

   for (octave_idx_type ii (0); ii < args(0).length (); ii++)
       {
       justchange_input(ii) = justchange_input(ii) * 1 ;
       }

  retval = justchange_input;

  return retval;
}

fails to compile, with error message

justchange.cc:13: error: no match for ‘operator=’ in
‘justchange_input.ComplexColumnVector::<anonymous>.MArray<std::complex<double>
>::<anonymous>.Array<T>::operator() [with T = std::complex<double>](ii) =
operator*(const octave_value&, const octave_value&)(((const octave_value&)(&
octave_value(1))))’
/usr/include/c++/4.3/complex:1224: note: candidates are:
std::complex<double>& std::complex<double>::operator=(double)
/usr/include/c++/4.3/complex:1159: note:                
std::complex<double>& std::complex<double>::operator=(const
std::complex<double>&)

and this essentially what I am trying to do.




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