Re: fsolve and parameter dependent functions

[Ivan Sutoris]

On Wed, Jun 10, 2009 at 3:57 PM, Kenneth Duncan
Strouts<address@hidden> wrote:
> Say I have a set up like this;
>
> function y = f(x)
>   ... stuff ...
> endfunction
>
> Then I can call fsolve("f",init) with init specifying initial
> conditions.  And it works really nicely.
>
> However what if the function is to include a parameter,
>
> function y = f(x,p)
>   ... stuff ...
> endfunction
>
> I want to specify p *when I call* fsolve.  Is this possible?  One
> could conceivably pass p through initial conditions and treat it as a
> variable, however I don't want to do this!  Is there a cleaner way to
> do it?
>
> Thanks!

You can use anonymous function:

par = 1; % or whatever you need
solfun = @(x) f(x, par);
x = fsolve(solfun, init)

Regards
Ivan Sutoris