Re: FFT and 'uneven' time data

[macy]

>
> On Apr 21, 2009, at 4:45 PM, address@hidden wrote:
>
>> How do I easily handle obtaining an FFT when the data is NOT evenly
>> spaced
>> in time?
>>
>> I wrote my own program to create a new variable with evenly spaced
>> data
>> using linear interpolation, which works fine, except it does not
>> decimate,
>> it only adds in so the smallest step becomes the final step [obviously
>> creating a huge data base], plus with data that has jitter, does not
>> work
>> as well.
>>
>> Is there some way to obtain an FFT directly given the time base of the
>> data is not evenly spaced *and* contains jitter?
>>
>> Robert
>
> The simple and somewhat dirty solution is to interpolate your original
> data using a smooth interpolation to evenly spaced times. Otherwise,
> take a look at this:
>
> http://pubs.acs.org/doi/abs/10.1021/es0700247
>
> Cheers
> Matthias

Matthias,

Thank you for this URL.  Opened up a whole new area in looking for "Lomb
Periodogram"

Robert