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Re: Piecewise function in octave


From: Ben Abbott
Subject: Re: Piecewise function in octave
Date: Wed, 15 Oct 2008 18:54:43 -0400

".*" is element by element multiplication, where "*" is matrix multiplication.

        f = @(t) a(t) .* (t<t0) + b(t) .* (t==t0) + c(t) .* (t>t0);

For example,

        octave-3.1.51+:1> a = @(t) -1;
        octave-3.1.51+:2> b = @(t) 0;
        octave-3.1.51+:3> c = @(t) 1;
octave-3.1.51+:4> f = @(t,t0) a(t) .* (t<t0) + b(t) .* (t==t0) + c(t) .* (t>t0);
        octave-3.1.51+:5> t = (-10):10;
        octave-3.1.51+:6> x = f(t,0);
        octave-3.1.51+:7> x
        x =
-1 -1 -1 -1 -1 -1 -1 -1 -1 -1 0 1 1 1 1 1 1 1 1 1 1
        octave-3.1.51+:8> x = f(t,3)
        x =
-1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 0 1 1 1 1 1 1 1

Ben


On Oct 15, 2008, at 5:42 PM, genehacker wrote:


Hi Carlo,

Can you please tell what .* do to the equation. Also how would you write
a generalised piecewise function like

f(t) =  a(t) t < t0
        b(t) t = t0
        c(t) t > t0

thanks in advance,
k3.


Carlo de Falco-2 wrote:


On 15/ott/08, at 21:57, genehacker wrote:

Hi,

 I am looking for a code that can specify a function f(t)
piecewise, i.e.
that can be defined according to intervals based on value of t. I
want to
integrate one of these in an anonymous function g(x,t).

f(t) = sin(t)  t<pi
     0         t>=pi

cheers
k3

to implement the example above you could use

f = @(t) sin(t) .* (t<pi) ;

c.

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