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Re: enum in octave?


From: Carlo de Falco
Subject: Re: enum in octave?
Date: Mon, 13 Oct 2008 14:37:32 +0100


On 13/ott/08, at 08:28, Matthias Brennwald wrote:

Jim

How about this (in Octave):

---------------
R = 0;
K = 1;
BOB = ...; (insert whatever value needs to go here)
y[BOB] = p[R]*y[BOB]*(1 - y[BOB]/p[K]);
---------------

actually in Octave the above should read:

R = 1;
K = 2;
BOB = ...; (insert whatever value needs to go here)
y(BOB) = p(R)*y(BOB)*(1 - y(BOB)/p(K));

Cheers
Matthias

c.



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