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Help/ advice on using bicubic () or interp2()
From: |
Prof M. N. Anandaram |
Subject: |
Help/ advice on using bicubic () or interp2() |
Date: |
Tue, 12 Aug 2008 19:41:17 -0700 (PDT) |
Hello all:
When I run the following script on the data given after it,
%=======================================
Xt = zeros(10,8);
for id = 1 : 8, Xt(1:10, id) = tabtm(1:10, 1); endfor % here tabtm(10,1)
becomes Xt(10,8)
disp(size(Xt))
disp(size(CSext));
CSi = bicubic(tabtm, tabdm, CSext, 6.89, 0.555);
disp(CSi)
%=========================================
tabtm= and tabdm =
(10,1) size (10,8)
[9.00 ; [ 3.000 4.000 5.000 6.000
7.000 8.000 9.000 10.000
8.70 ; 2.000 3.000 4.000 5.000
6.000 7.000 8.000 9.000
8.30 ; 1.000 2.000 3.000 4.000
5.000 6.000 7.000 8.000
8.00 ; 0.000 1.000 2.000 3.000
4.000 5.000 6.000 7.000
7.70 ; -1.000 0.000 1.000 2.000
3.000 4.000 5.000 6.000
7.30 ; -2.000 -1.000 0.000 1.000
2.000 3.000 4.000 5.000
7.00 ; -3.000 -2.000 -1.000 0.000
1.000 2.000 3.000 4.000
6.70 ; -4.000 -3.000 -2.000 -1.000
0.000 1.000 2.000 3.000
6.30 ; -5.000 -4.000 -3.000 -2.000
-1.000 0.000 1.000 2.000
6.00 ] -6.000 -5.000 -4.000 -3.000
-2.000 -1.000 0.000 1.000]
CSext = size (10,8):
[ -1.17457388 -1.17457388 -1.17198494 -1.15801520 -1.12378216 -0.92445304
0.02530587 4.63848926
-1.01144104 -1.01099538 -1.00788851 -0.98716278 -0.92081875 -0.77989191
0.01703334 2.31806333
-0.86012091 -0.85698520 -0.85078089 -0.81247928 -0.67985371 -0.44733178
0.18184359 2.04139269
-0.78781240 -0.78515615 -0.77728353 -0.73048706 -0.57186521 -0.24641694
0.17897695 1.51851394
-0.74472749 -0.74232143 -0.73048706 -0.67778071 -0.49349497 -0.08460016
0.41329976 1.17026172
-0.71669877 -0.70996539 -0.68193667 -0.57348874 -0.29756946 0.28555731
0.96047078 1.49831055
-0.70553377 -0.69680394 -0.65169514 -0.49349497 -0.14569396 0.37657696
1.20682588 1.79795964
-0.69897000 -0.67985371 -0.58838029 -0.31605287 0.19033170 0.79726754
1.29446623 2.15836249
-0.68193667 -0.56543110 -0.14630179 0.61489722 1.47421626 2.14301480
2.45636603 2.55750720
-0.64206515 -0.50584541 -0.15119530 0.66181269 1.71767050 2.74741181
3.33645973 3.44715803]
Output of Octave3.0.1 is the following(in WinXP SciTE window):
10 8
10 8
error: X, Y and Z must be martrices of same size
error: evaluating if command near line 73, column 5
error: evaluating if command near line 51, column 3
error: called from `bicubic' in file
`H:\Octave\share\octave\3.0.1\m\general\bicubic.m'
error: evaluating assignment expression near line 1032, column 5
error: near line 1032 of file `rdcs1970.m'
>Exit code: 1
I tried interp2() also . Similar response follows.
Can you tell me what I should do or be doing?
Anandaram
- Help/ advice on using bicubic () or interp2(),
Prof M. N. Anandaram <=