Re: size of NDArrays

[Thomas L. Scofield]

Oops.  m.ndims () is what I meant.

Anyway, your response tells me just what I needed to know.  Heretofore I have assumed a dim_vector could have length 1, 2 or 3 only, and that after that one had to use an Array<octave_idx>.

Can I safely assume that a dim_vector is simply an Array<octave_idx>, but that there are constructors for dim_vector only in the cases where lengths are 1, 2 or 3?

Thanks.

On Aug 11, 2008, at 2:50 PM, Søren Hauberg wrote:

man, 11 08 2008 kl. 14:37 -0400, skrev Thomas L. Scofield:

I can use

   m.dims ()

to find out how many coordinates the new array m has.  But how do I

find out the range of values in a particular coordinate?  That is, if

the original call within Octave sent a matrix A satisfying

   size(A) = [256   256   3   10]

which is what is stored in the argument param, then

   m.dims ()

would equal 4.  But what method tells me that the largest valid entry

in the 4th position is 9?

Actually, m.dims () return a 'dim_vector' which would contain the values

[256   256   3   10]. I can't remember the exact syntax but I believe

you can do something like this:

  dim_vector dims = m.dims ();

  for (int i = 0; i < dims.length (); i++)

    printf ("%d ", dims (i));

which should print "256 256 3 10 ". BTW. the m.ndims () return the

number 4 in this case.

Søren

Thomas L. Scofield

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Associate Professor

Department of Mathematics and Statistics

Calvin College

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Thomas L. Scofield

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Associate Professor

Department of Mathematics and Statistics

Calvin College

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