Francesco Potorti` wrote:
Here is my question. In Mathematica, there exists a function called
Drop, which I often use to manipulate lists, e.g., Drop[ list,
{m, n}
] returns the argument list with the elements m through n omitted
from
the list (the resultant list is shorter for (n - m + 1) elements).
Does anything similar already exist in Octave? I know I can
program it
myself, but I wouldn't want to reinvent the wheel. :)
Use indexing. For instance [list(1:m-1), list(n+1:end)] could do
what
you want.
Assuming, as Michael did, that you want to remove elements from an
array, you can alternatively do
list(m:n)=[];
And if you don't want to actually remove the value from your list, but
you just want to do a calculation on a subset (not quite what you
asked,
but often what you asked for is for this purpose), you can index the
vector:
with the indexes themselves
list([1:m-1 n+1:length(list)])
or with a logical vector
mask = false(size(list));
mask(m:n) = true;
list(mask)
Have a good day,
Bill