Re: Reverse concatenation?

[David Bateman]

Emily Moberg wrote:
> Sorry! So, if i have a matrix like this A=[6;1;2;3;4;6;3;3;3;6] I
> would like to be able to access the values between the 6's as matrices
> on their own, so B=[1;2;3;4], C=[3;3;3]. I'm a really new user to
> octave so I really have no idea if this is even possible.  Thanks so
> much for your time.

idx = find(A == 6);
B =eval(["{" sprintf("A(%d:%d) ",[idx(1:end-1)+1, idx(2:end)-1]'),"}"])

Creates a cell array with the values you want

D.


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