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NaN slowdown with some processors


From: Olli Saarela
Subject: NaN slowdown with some processors
Date: Wed, 04 Jun 2008 09:11:15 +0300
User-agent: Thunderbird 2.0.0.14 (Windows/20080421)

Hello,

I'm planning to buy a new desktop machine, and since my computations utilize NaN values heavily, I'd like to know whether Intel Core 2 processors suffer from the same slowdown with NaN values as Pentium. For details, see http://www.cygnus-software.com/papers/x86andinfinity.html

If someone has Octave on a machine with a Core 2 processor, please run the following commands and tell the results. (Or a more detailed test from ftp://ftp.cygnus-software.com/pub/specialnumbers.zip)

    a=zeros(300,300);tic;b=(1.0+a)*a;toc
    a=zeros(300,300);tic;b=(NaN+a)*a;toc

Below are results from my current machines. Since SSE2 in Pentium isn't affected with the slowdown, it seems that for some reason the commands above don't utilize SSE2. AMD processors aren't affected.

Pentium M, Octave 3.0.1 MSVC2005 SSE2
    octave-3.0.1.exe:8> a=zeros(300,300);tic;b=(1.0+a)*a;toc
    Elapsed time is 0.0430298 seconds.
    octave-3.0.1.exe:9> a=zeros(300,300);tic;b=(NaN+a)*a;toc
    Elapsed time is 28.8307 seconds.

Pentium 4 (Family 15, Model 2), Octave 3.0.1 MSVC2005 SSE2
    octave-3.0.1.exe:2> a=zeros(300,300);tic;b=(1.0+a)*a;toc
    Elapsed time is 0.0257161 seconds.
    octave-3.0.1.exe:3> a=zeros(300,300);tic;b=(NaN+a)*a;toc
    Elapsed time is 15.7125 seconds.

AMD Turion 64 X2, Octave 3.0.1 MSVC2008 SSE3
    octave-3.0.1.exe:3> a=zeros(300,300);tic;b=(1.0+a)*a;toc
    Elapsed time is 0.0244939 seconds.
    octave-3.0.1.exe:4> a=zeros(300,300);tic;b=(NaN+a)*a;toc
    Elapsed time is 0.0251131 seconds.

Thank you,
  Olli



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