help-octave
[Top][All Lists]

## Re: Question About Plotting Trigonometric Functions

 From: Ben Abbott Subject: Re: Question About Plotting Trigonometric Functions Date: Mon, 24 Dec 2007 11:11:59 +0800

The period of your sine wave is 1/400 = 0.0025, while the distance between time indices is 0.1 (40 cycles). Each sample is very a multiple of a cycle. Thus, you are evaluating sin(2*pi*N) for N = 0, 40, 80, 120, 160, 200. Each of these should ideally give a result of zero. Your result is within expected numerical precision.
```
To obtain a more representative plot of the sine wave, try

f = 400;
t = (0:0.01:1.0)/f;
plot (t, sin (2*pi*f*t))

Ben

On Dec 24, 2007, at 7:10 AM, Malstygian wrote:

```
```
I would like to graph the following puretone sine wave:

f = 400;
t = 0:0.1:0.5;
plot(t, sin(2*pi*f*t))

However, the plot this generated did not look correct as confirmed by
```
plotting the same equation using my TI-83 graphing calculator. The picture
```of the result is shown below.  What am I doing wrong?

Thank you

http://www.nabble.com/file/p14482857/sin_graph.png
--
View this message in context:
Sent from the Octave - General mailing list archive at Nabble.com.

_______________________________________________
Help-octave mailing list
```