Re: AGAIN A SIMPLY QUESTION

[James Sherman Jr.]

You could always do some simple multiplication:

B = ones(3, 1) * A;

I can't think of a faster way, since writing a for loop to replace
each row individually is bound to be slower.

James

On 9/11/07, Oscar Bayona Candel <address@hidden> wrote:
>
>
> Hi,
>
>  There is any function that if I want to replace a row vector in all rows of
> a matrix could do it?
>
>  In example:
>
>  A=[ 2.5 3.6 2 3 9] %this is an 1x5 vector
>
>  B=[1 1 1 1 1
>  1 1 1 1 1
>  1 1 1 1 1] % B is an 3x5 matrix
>
>  I number of colums of A and B always coincide how can I replace all rows of
> B for A so that
>
>  I obteine this result?
>
>  (this should be the result)
>
>  B=[2.5 3.6 2 3 9
>  2.5 3.6 2 3 9
>  2.5 3.6 2 3 9]
>
>
>  As always, thanks in advance, and best regards. Sorry again if I express
> incorrectly.
>
>
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