Re: Weighted Moving Average

[Søren Hauberg]

Can't you do this with a convolution? That is,

function retval = wma(y)
  w = [1, 2, 1]/4;
  retval = conv(y, w);
endfunction

Søren

Luca Delucchi skrev:
> Hi, I can do a function on Weighted Moving Average where the value are
> take in automatic mode? this my idea
>
> #y=[y1,y2,y3,y4,y5]
> function wma(y)
> (y1+2*y2+y3)/4
> (y2+2*y3+y4)/4
> etc
> etc
> end function
>
> I could not repeat the formula (y1+2*y2+y3)/4 (because if the long of
> vector is different i must change the function) but have only one
> formula that use the formula for all values of vector
>
> I hope I've given a clear explanation
>
> Luca
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