Re: impulse function

[James Sherman Jr.]

I'm a bit confused by your code here:

for n = 0:25
        for m = 0:10
                x(n) = (m+1)*(impulse(n-(2*m))-impulse(n-(2*m)-1));

       endfor;
       plot(x(n));
endfor;

First off, I think you can just implement the impulse function using just == 
(i.e. impulse(n) = 1 if and only if n = 0, otherwise = 0)
and secondly, you're not performing any summation in the m loop, you're essentially assigning x(n) the value when m = 10 (the last value in the loop).

What I think you want is this:
first, define imp as:
------
function x = imp(n)

if n == 0,
  x = 1;
else
  x = 0;
end

return
------

Then, your loop would look something like:
------
x = zeros(1,26);
index = [0:25];

for n = index
  for m = 0:10
    x(n+1) = x(n+1) + (m+1)*(imp(n-(2*m))-imp(n-(2*m)-1));
  end
end
plot(index, x);
-------

At least, I think this is what you're going for.

James Sherman

On 8/7/07, brito.rn <address@hidden> wrote:

Hi,

I need to plot a sequence of samples of a equation that has impulses.

The sequence is here:
x[n] = sum((m+1)*[impulse(n-2m)-impulse(n-2m-1)]), with the sum of m from 0 to 10 and n from 0 to 25.

A simple code for that can be:

for n = 0:25
for m = 0:10
x(n) = (m+1)*(impulse(n-(2*m))-impulse(n-(2*m)-1));
endfor;
plot(x(n));
endfor;

but, the problem is: the imput impulse function format is sys type. I don't have idea about how I can use this
sys format for my equation.

I need help about how I can plot that sequence with impulses.

regards,

Brito.


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