Re: Simple routine won't run.

[Søren Hauberg]

Hi,
  A parse error means you've written something Octave can't understand. 
Octave realises that it doesn't understand what you wrote around line 
16. Usually the error is on line 16 or the line before. Look there for 
something that seems wrong. There is too much code in your example for 
me to look for the error. I do see that you write something

  ...k-j)log((d/2)^ ...

which is correct. Are you missing a * ? That is, did you want to write

  ...k-j) * log((d/2)^ ...

?

Søren
David Mebane skrev:
> Hello
>
> Have written a (very first) octave routine:
>
> [begin code]
> function fun=ent3(d)
>
> x31=0;
> for i = 0:1
> for j = 0:1
> for k = 0:1
> x31
> +=(d^i*(1-d)^(1-i)*(d/2)^(k+j)*(1-d/2)^(2-k-j))*log(d^i*(1-d)^(1-i)*(d/2)^(k+j)*(1-d/2)^(2-k-j));
> endfor
> endfor
> endfor
>
> x21=0;
> for i=0:1
> for j=0:1
> x21 +=
> (d^i*(1-d)(1-i)*(d/2)^j*(1-d/2)^(1-j))log(d^i*(1-d)(1-i)*(d/2)^j*(1-d/2)^(1-j));
> endfor
> endfor
>
> x22=0;
> for j=0:1
> for k=0:1
> x22 += (d/2)^(k+j)*(1-d/2)^(2-k-j)log((d/2)^(k+j)*(1-d/2)^(2-k-j));
> endfor
> endfor
>
> fun = -12*x31 + 16*x21 + 6*x22 - 5(d*log(d) + (1-d)*log(1-d));
>
> endfunction
> [end code]
>
> Running this gets me:
>
> [begin octave]
> octave:5> ent3(0.1)
> parse error near line 16 of file /home/dm215/Desktop/ent3.m
>
>   syntax error
>
> > > > x21 +=
> (d^i*(1-d)(1-i)*(d/2)^j*(1-d/2)^(1-j))log(d^i*(1-d)(1-i)*(d/2)^j*(1-d/2)^(1-j));
>                                         ^
>
> error: `ent3' undefined near line 5 column 1
> [end octave]
>
> which I don't completely understand.  Any thoughts?
>
>
> Thanks,
> -David
>
>
>
>
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